27y^2-28y+1=0

Solution for 27y^2-28y+1=0 equation:

27y^2-28y+1=0

a = 27; b = -28; c = +1;
Δ = b2-4ac
Δ = -282-4·27·1
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-26}{2*27}=\frac{2}{54}
=1/27
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+26}{2*27}=\frac{54}{54}
=1
$